In a `triangleABC`,`sqrt[{(s-a)(s-b)}/{s(s-c)}]` is:

In a triangleABC, s/R=

In a triangleABC, s/R=

If, in triangleABC, (s-a)(s-b)=s(s-c) , then: angleC =

In triangleABC, s(s-c)tan((C)/(2))=

In triangleABC, s(s-b)tan((B)/(2))=

In triangleABC, s(s-a)tan((A)/(2))=

In Heron's formula , area of triangle =sqrt(s(s-a)(s-b)(s-c)), s is …………………..of the triangle.

(a) Solve the equation sqrt(6-4x-x^2)=x+4 OR (b) Prove that in any DeltaABC,Delta=sqrt(((s-a)(s-b))/(s(s-c))) , where s is the semi - perimeter of DeltaABC ?

In triangleABC if c^2=a^2+b^2 then 4s(s-a)(s-b)(s-c)=