The amount of energy when millon atoms of iodine are completely converted into `I^(-)` ions in the vapour state according to the equation, `I(g) +e^(-)(g) rarr I^(-)(g) is 5.0 xx 10^(-13)J`.

The amount of energy when million atoms of iodine are completely converted into I^(-) ions in the vapour state according to the equation, I(g) +e^(-)(g) rarr I^(-)(g) is 5.0 xx 10^(-13)J .

The amount of energy when million atoms of iodine are completely converted into I^(-) ions in the vapour state according to the equation, I_((g))+e^(-) to I^(-)_((g)) is 4.9X10^(-13) J.What would be the electron gain enthalpy of iodine in terms of KJ mol^(-1) and eV per atom?

The amount of energy when million atoms of iodine are completely converted into I^(-) ions in the vapour state according to the equation, I_((g))+e^(-) to I^(-)_((g)) is 4.9X10^(-13) J.What would be the electron gain enthalpy of iodine in terms of KJ mol^(-1) and eV per atom? (A)295 , 3.06 (B)− 295, − 3.06 (C)439 , 5.09 (D)− 356 , − 7.08

The amount of energy when million atoms of iodine are completely converted into l^- ions in the vapour state according to the question: I(g)+e^-(g) rarr I^-(g) is 5xx10^(-13) J What would be electron gain enthalpy of iodine in terms of kj/mole

The amount of energy released when 1 xx10^10 atoms of chlorine in vapour state are converted to Cl^(–1) ions according to the equation, Cl(g) + e^(-) to Cl^(-) (g) " is " 57.86 xx 10^(-10) J Calculate the electron gain enthalpy of chlorine atom in terms of kJ "mol"^(–1 ) and eV per atom.

The amount of energy released when 10^(12) atoms of Cl vapours are converted to Cl^(ɵ) ions, according to the equation : Cl_((g))+e^(-) rarr Cl_((g))^(ɵ) is 58 xx 10^(-10)J Calculate the Delta_(eg)H^(ɵ) of Cl atom in kJ mol^(-1) and eV "atom"^(-1) .

The amount of energy released when 10^(12) atoms of Cl vapours are converted to Cl^(ɵ) ions, according to the equation : C_((g))+e^(-) rarr Cl_((g))^(ɵ) is 58 xx 10^(-10)J Calculate the Delta_(eg)H^(ɵ) of Cl atom in kJ mol^(-1) and eV "atom"^(-1) .