`f(x)={[x]+[-x],` where `x!=2` and `lambda,` where If `f(x)` is continuous at `x=2` then, the value of `lambda` will be

f(x)={([x]+[x], "when" x ne 2),(lambda, "when" x = 2):} If f(x) is continuous at x = 2, the value of lambda will be

f(x) ={{:([x]+[-x], "when" , x ne 2),(lambda, "when", x =2):} , If f(x) is continous at x=2, the value of lambda will be:

f(x) = {:([x] + [-x] x ne 2),(" "lambda " " x = 2 ):} f(x) is continuous at x = 2 then lambda =

Consider f(x)={{:([x]+[-x],xne2),(lambda,x=2):} where [.] denotes the greatest integer function. If f(x) is continuous at x=2 then the value of lambda is equal to

Consider f(x)={{:([x]+[-x],xne2),(lambda,x=2):} where [.] denotes the greatest integer function. If f(x) is continuous at x=2 then the value of lambda is equal to

Given, f(x)={((x^4-256)/(x-4), x ne 4), ( lambda, x = 4):} . If f is continuous at x = 4, then the value of ^root(4)(lambda) must be

If f(x) = [x] + [-x], x ne 2 = lambda, x = 2 , then f is continuous at x = 2, provided lambda is equal to :

If f(x) = {((1-sinx)/(pi-2x), ",", x != pi/2),(lambda, ",", x = pi/2):} , be continuous at x = (pi)/2 , then the value of lambda is

If f(x) = {((1-sinzx)/(pi-2x), ",", x != pi/2),(lambda, ",", x = pi/2):} , be continuous at x = (pi)/2 , then the value of lambda is

f(x)={{:(,[x]+[-x], x ne 0),(,lambda,x=0):} Find the value of lambda , f is continuous at x=0?