A particle is moving in `x-y` plane with `y=x/2` and `V_(x)=4-2t`. The displacement versus time graph of the particle would be

A particle id moving in xy - plane with y = x//2 and v_x = 4 - 2t . Choose the correct options.

A particle id moving in xy - plane with y = x//2 and v_x = 4 - 2t . Choose the correct options.

A particle is moving in X-Y plane that x=2t and y=5sin(2t). Then maximum speed of particle is:

Figure shows the displacement time graph of a particle moving on the X-axis

The position of a particle moving in x-y plane changes with time t given by vecx= 3t^2hati + 9thatj . The acceleration of particle would be

Figures shows the displacement-time graph of a particle moving along x-axis.

A particle moves in x-y plane according to the law x = 4 sin 6t and y = 4 (1-cos 6t) . The distance traversed by the particle in 4 second is ( x & y are in meters)

A particle moves in x-y plane according to the law x = 4 sin 6t and y = 4 (1-cos 6t) . The distance traversed by the particle in 4 second is ( x & y are in meters)

A particle moves in x-y plane according to the law x = 4 sin 6t and y = 4 (1-cos 6t) . The distance traversed by the particle in 4 second is ( x & y are in meters)