The equivalent weight of potash alum
`(K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O)` is

Find the equivalent weight of (a) CaCO_(3) (b) K_(2)SO_(4). Al_(2)(SO_(4))_(3). 24H_(2)O (Mol mass = M)

Given the ionic equivalent conductivities for the following ions : lambda^(@)._(eq)K^(o+)=73.5cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)Al^(3+)=149cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)SO_(4)^(2-)=85.8cm^(2)ohm^(-1)eq^(-1) The wedge_(eq)^(@) for potash alum (K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O) is :

Given the ionic equivalent conductivities for the following ions : lambda^(@)._(eq)K^(o+)=73.5cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)Al^(3+)=149cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)SO_(4)^(2-)=85.8cm^(2)ohm^(-1)eq^(-1) The wedge_(eq)^(@) for potash alum (K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O) is :

The aqueous solution of potash alum [K_(2)SO_(4)*Al_(2)(SO_(4))_(3)*24H_(2)O] is acidic due to

What is the relation between molar conductivity (wedge_(m)) and equivalent conductivity (wedge_(eq)) of potash alum [K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H _(2)O ?

What is the relation between molar conductivity (wedge_(m)) and equivalent conductivity (wedge_(eq)) of potash alum [K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H _(2)O ?

The weight (in gram) of pure potash alum [K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O] which contains 0.64 kg oxygen. (Atomic weight of K = 39, S = 32, Al = 27 )