The system shown is figure consists of `3` springs and two rods. If the temperature of the rod is increased by `DeltaT`, then the total energy stored in three springs is `beta xx (99)/(484)kL^(2)alpha^(2)(DeltaT)^(2)`. Determine the value of `beta`. The spring are initially relaxed and there is no friction anywhere. For rod the coefficient of linear expansion is `alpha`

The systeam shown is figure consists of 3 springs and two rods. If the temperature of the rod is increased by DeltaT , then the total energy stored in three springs is beta xx (99)/(484)kL^(2)alpha^(2)(DeltaT)^(2) . Datermine the value of beta . The soring are initially relaxed and there is no frication anywhere. For rod the coefficient of linear expansion is alpha

The system shown in figure consists of three springs and two rods as shown. If the temperature of the rods is increased by delta(t) calculate the energy stored in each of the springs. The springs are initially relaxed. There is no friction.

The moment of ineratia of a uniform thin rod about its perpendicular bisector is I . If the temperature of the rod is increased by Deltat , the moment of inertia about perpendicular bisector increases by (coefficient of linear expansion of material of the rod is alpha ).

When solid is heated , its length changes according to the relation l=l_0(1+alphaDeltaT) , where l is the final length , l_0 is the initial length , DeltaT is the change in temperature , and alpha is the coefficient of linear is called super - facial expansion. the area changes according to the relation A=A_0(1+betaDeltaT) , where A is the tinal area , A_0 is the initial area, and beta is the coefficient of areal expansion. The coefficient of linear expansion of brass and steel are alpha_1 and alpha_2 If we take a brass rod of length I_1 and a steel rod of length I_2 at 0^@C , their difference in length remains the same at any temperature if