If `omega(ne 1)` be a cube root of unity and `(1+omega)^(7)=A+Bomega`, then A and B are respectively the numbers.

If omega ( != 1) is a cube root of unity and (1+omega)^7 =A+B omega , then A and B are respectively the numbers

Select the correct answer from the given alternatives. If (omega !=1) is a cube root of unity and (1 + omega)^7 = A + Bomega . Then A and B are respectively the numbers,

If omega (ne 1) is a cube root of unity and (1 + omega)^(2017) = A + B omega . Then A and B are respectively the numbers

If omega(ne1) is a cube root of unity and (1+omega)^7=A+B_omega then (A,B) equals

If omega is a complex cube root of unity and (1+omega)^7=A+Bomega then A and B are respectively.