A satellite of mass 2000 kg is revolving around the earth in a circular orbit of radius `4xx10^(4)` km. The gravitational force exerted by the satellite on the earth is ________. [Mass of the earth `= 6xx10^(24)kg, G=6.67xx10^(-11)Nm^(2)//kg^(2)`]

A satellite of mass 200 kg revolves around of mass 5 xx 10^(30) kg In a circular orbit of radius 6.6 xx10^(6) m . Binding energy of the satellite is

A satellite of mass 200 kg revolves around of mass 5 xx 10^(30) kg In a circular orbit of radius 6.6 xx10^(6) m . Binding energy of the satellite is

Calculate the height above the earth at which the geostationary satellite is orbiting the earth. Radius of earth = 6400km. Mass of earth = 6 xx 10^(24) kg. G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

A satellite is revolving round the earth at a height of 600 km. find a. The speed of the satellite and b. The time period of the satellite. Radius of the earth =6400 km and mass of the earth =6xx10^24kg .

The distance between centre of the earth and moon is 384000 km . If the mass of the earth is 6xx10^(24) kg and G=6.66xx10^(-11)Nm^(2)//kg^(2) . The speed of the moon is nearly

Calculate (i) kinetic energy (ii) potential energy and (iii) total energy of a satellite of mass 200 kg orbiting around the earth in an orbit of height 100 km from the surface of earth. Given, mass of earth = 10^(25) kg ,radius of earth = 6.4 xx 10^(6) m, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .