P is a point on the parabola `y^2=4x` and Q is IS a point on the line `2x +y+4=0`. If the line `x-y + 1= 0` is the perpendicular bisector of PQ, then the co-ordinates of P can be:

P is a point on the circle x^2+y^2=9 Q is a point on the line 7x+y+3=0 . The perpendicular bisector of PQ is x-y+1=0 . Then the coordinates of P are:

P is a point on the circle x^(2)+y^(2)=9Q is a point on the line 7x+y+3=0. The perpendicular bisector of PQ is x-y+1=0 Then the coordinates of P are:

Let P be a point on the circle x^(2)+y^(2)=9 , Q a point on the line 7x+y+3=0 , and the perpendicular bisector of PQ be the line x-y+1=0 . Then the coordinates of P are

If Q is the point on the parabola y ^(2) =4x that is nearest to the point P (2,0) then PQ =

If P is point on the parabola y ^(2) =8x and Q is the point (1,0), then the locus of the mid point of the line segment PQ is

Let P be the foot of perpendicular drawn from a point Q on the line x + y +4 = 0 to the line 5x + y = 0. If P is the image of point R(12, 0) about the line x + y = 2, then coordinates of Q are

Let P be the foot of perpendicular drawn from a point Q on the line x + y +4 = 0 to the line 5x + y = 0. If P is the image of point R(12, 0) about the line x + y = 2, then coordinates of Q are

Normal to the parabola y^(2)=8x at the point P(2,4) meets the parabola again at the point Q . If C is the centre of the circle described on PQ as diameter then the coordinates of the image of point C in the line y=x are