Let `A = [[cos alpha, -sin alpha],[sin alpha, cos alpha]]` and `A^(32) = [[0, -1],[1,0]]` (A) 0 (B) `(pi)/(32)` (C) `(pi)/(64)` (D) `(pi)/(16)`

Let A=[[cos alpha,-sin alphasin alpha,cos alpha]] and A^(32)=[[0,-11,0]] (A) 0 (B) (pi)/(32) (C) (pi)/(64) (D) (pi)/(16)

If A=[(cos alpha, -sin alpha, 0),(sin alpha, cos alpha,0),(0,0,1)] then A^(-1) is

If A=[(cos alpha, - sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)] then (AdjA)^(T)=

Let A=([cos alpha,-sin alphasin alpha,cos alpha]),(alpha in R) such that A^(32)=([0,-11,0]). Then a value of alpha is:

Find inverse of the matrix A=[[cos alpha, -sin alpha, 0 ],[ sin alpha, cos alpha, 0],[ 0, 0, 1]]

Let alpha=(pi)/(5) and A,=[[cos alpha,sin alpha-sin alpha,cos alpha]] then B=A^(4)-A^(3)+A^(2)-A is

Let A = [{:(cos alpha,- sin alpha ), ( sin alpha , cos alpha ):}], (a in R) such that A ^(32) = [{:(0,-1), (1, 0):}] is the value of alpha is (pi)/(2^(k)), then the value of k is

If F(alpha)=|(cos alpha, -sin alpha, 0),(sin alpha, cos alpha, 0),(0,0,1)| then det F(alpha)=

Let A = [{:("cos"alpha, -"sin"alpha), ("sin"alpha, "cos"alpha"):}], (alpha in R) such that A^(32) = [{:(0, -1), (1, 0):}] . Then, a value of alpha is