A proton has kinetic energy `E = 100 keV` which is equal to that of a photo is `lambda_(1)` . The ratio of `k_(2) // lambda_(1) ` is proportional to

A proton has kinetic energy E = 100 keV which is equal to that of a photon. The wavelength of photon is lamda_(2) and that of proton is lamda_(1) . The ratio of lamda_(2)//lamda_(1) is proportional to

A proton has kinetic energy E = 100 keV which is equal to that of a photon. The wavelength of photon is lamda_(2) and that of proton is lamda_(1) . The ratio of lamda_(2)//lamda_(1) is proportional to

A proton with KE equal to that a photono (E = 100 keV). lambda_(1) is the wavelength of proton and lambda_(2) is the wavelength of photon. Then lambda_(1)/lambda)_(2) is proportional to:

When kinetic energy of proton is equal to energy of photon then ratio of de-Broglie wavelength of proton and photon is proportional to …..

A photon and an electron have equal energy E . lambda_("photon")//lambda_("electron") is proportional to

A photon and an electron have equal energy E . lambda_("photon")//lambda_("electron") is proportional to