For liquid enthalpy of fusion is `1.435 kcal mol^(-1)` and molar entropy change is `5.26 cal mol^(-1) K^(-1)`. The melting point of the liquid is

For a liquid, enthalpy of fusion is 1.435 kCal mol^(-1) and molar entropy change is 5.26 cal mol^(-1) K^(-1) . The freezing point of liquid in celcius will be ________

Enthalpy of fusion of a liquid is 1.435Kcal mol^(-1) and molar entropy change is 5.26cal mol^(-1)K^(-1) Hence melting point of liquid is

For a liquid, enthalpy of fusion is 1.435 xx 10^(3) cal mol^(-1) and molar entropy change is 5.26 cal mol^(-1) . Calculate the melting point of the liquid.

Molar heat of vaporisation of a liquid is 6 kJ mol^(-1) . If the entropy change is 16 J mol^(-1) K^(-1) the boiling point of the liquid is

The enthalpy of vaporisation of a liquid is 30 kJ mol^(-1) and entropy of vaporisation is 75 J mol^(-1) K^(-1) . The boiling point of the liquid at 1atm is :

The enthalpy of vaporisation of a liquid is 30 kJ mol^(-1) and entropy of vaporisation is 75 J mol^(-1) K^(-1) . The boiling point of the liquid at 1atm is :

The enthalpy of vaporisation of a liquid is 30 kJ mol^(-1) and entropy of vaporisation is 75 J mol^(-1) K^(-1) . The boiling point of the liquid at 1atm is :

The enthalpy of vaporisation of a liquid is 30 kJ mol^(-1) and entropy of vaporisation is 75 J mol^(-1) K^(-1) . The boiling point of the liquid at 1atm is :

Molar heat of vapourisation of a liquid is 4.8 kJ "mol"^(-1) . If the entropy change is 16 J mol^(-1) K^(-1) , the boiling point of the liquid is