Angle between the lines `2x^(2)-3xy+y^(2)=0` is

Angle between the lines 2x^(2)-7xy +3y^(2)=0 is

The angle between the lines 2x^(2)-7xy+3y^(2)=0 is 60^(0)2.45^(0)3tan^(-1)(7/6) 4.30^(@)

The angle between the lines x^(2)+4xy+y^(2)=0 is

The joint equation of lines which bisect the angle between the two lines x^(2)+3xy+2y^(2)=0 is

If the acute angle between the lines ax^(2)+2hxy+by^(2)=0 is congruent to the acute angle between the lines 3x^(2)-7xy+4y^(2)=0 , then

Find the angle between the lines 3x^(2)-10xy-3y^(2)=0 :

If the angle between the lines represented by ax^(2) + 2hxy + by^(2) = 0 is equal to the angle between the lines 2x^(2) - 5xy + 3y^(2) = 0 , then show that 100(h^(2)-ab) = (a+b)^(2) .

The angle between the lines x^(2) + 4xy + y^(2) = 0 is

Measure of angle between lines 3x^(2)-8xy-3y^(2)=0 is

If theta is the acute angle between the lines given by ax^(2) + 2hxy + by^(2) = 0 then prove that tan theta = |(2 sqrt (h^(2) - ab))/(a + b)| . Hence find acute angle between the lines 2x^(2) + 7xy + 3y^(2) = 0