If `f:R to R, g:R to R` and `h : R to R` be defined respectively by `f(x)=sinx, g(x)=3x-1` and `h(x)=x^(2)-4`, then the value of `[ho(gof)]((pi)/(2))` is -

Let the mappings f:R to R and g:R to R be defined respectively by f(x)=5|x|-x^(2) and g(x)=2x-3 . Then the value of (gof)(-2) is -

If f : R to R, g : R to R and h: R to R is such that f (x) =x ^(2) , g (x) = tan x and h (x) = log x, then the value of [ho(gof),if x = (sqrtpi)/(2) will be

If f:R to R and g:R to R are defined by f(x)=(2x+3) and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

If f : R to R and g:R to R are defined by f(x)=2x+3 and g(x)=x^(2)+7 , then the values of x such that (gof)(x)=8 are -

Let the function f : R to R , g : R to R , h : R to R be defined by f(x) = cos x,g(x) = 2x+1 and h(x) = x^(3)-x-6 , Find the mapping h o (go h) , hence find the value of h o (go f), hence find the value of ( h o (go f) ) (x) when x=(pi)/(3) and c=(2pi)/(3).

If f:R rarr R and g : R rarr R are defined by f(x) = 3x + 2 and g(x) = x^2 - 3 , then the value of x such that g(f(x))=4 are

Let f:R to R and g:R to R is define by f(x)=2x+3 and g(x)=3x-2 , then find (f circ g)^(-1)(x)

Let f:R to R and g:R to R is define by f(x)=2x+3 and g(x)=3x-2 , then find (g circ f)^(-1)(x)