Equation Of Trajectory

Equations of trajectory of a projectile are x=4 t, y= 3t - 5 t ^(2) , where x and y are in metre and t is in second . Find (i) maximum height attained by the projectille , (ii) horizontal range of the projectile .

An object is projected with a velocitiy of 20m//s making an angle of 45^(@) with horizontal. The equation for trajectory is h=Ax-Bx^(2) where h is height x is horizontal distance. A and B are constants. The ratio A.B is x/0.1 . Find value of x.(g=10m//s^(2))

If y = x - (1)/(2)x^(2) is the equation of a trajectory , find the time of flight.

The equation of a trajectory of a projectile is y=8x-4x^(2) . The maximum height of the projectile is ?

If y = x - (1)/(2)x^(2) is the equation of a trajectory , find the time of flight.

A particle travels according to the equation x=at^(3),y=bt^(3) . The equation of the trajectory is

A particle travels according to the equation x=at^(3),y=bt^(3) . The equation of the trajectory is

A projectile is fired horizontally with a velocity u, from a height h above the ground. Find the equation of the trajectory .