A simple pendulum of length `l_(1)` has frequency 1/4 Hz and another simple pendulum of length `l_(2)` has frequency 1/3 Hz. Then time period of pendulum of length `(l_(1)-l_(2))` is

A simple pendulum of length l_1 has frequency 1/4 Hz and another simple pendulum of length l_2 has frquency 1/3 Hz . Then time period of pendulum of length (l_1 + l_2) is

A simple pendulum of length l_(1) has a time period of 4 s and another simple pendulum of length l_(2) has a time period 3 s. Then the time period of another pendulum of length (l_(1)-l_(2)) is

A simple pendulum of length L_(1) has a time period T_(1) and of length L_(2) has a time period of T_(2) then the time period of pendulum of length (L_(1)+L_(2)) is

A simple pendulum of length 25 cm has a time period of 1 s and another pendulum of length 100cm has a time period of 2s. The time period of a simple pendulum of length 125 cm will be

Find the expression of time period of a simple pendulum of length l.

The l - T^(2) graph of a simple pendulum is an shown in the figure. The time period of the pendulum of length 0.5 mm is

If the inertial mass and gravitational mass of the simple pendulum of length l are not equal, then the time period of the simple pendulum is :