A proton accelerated through a potential `V` has de-Broglie wavelength `lamda`. Then, the de-Broglie wavelengthof an alpha-particle, when accelerated through the same potential `V` is

An electron of mass 'm', when accelerated through a potential V has de-Broglie wavelength lambda . The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be:

An electrono of mass m, when accelerated through a potential difference V, has de-Broglie wavelength lambda . The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference, will be:

An electron of mass m when accelerated through a potential difference V has de - Broglie wavelength lambda . The de - Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

An electron of mass m when accelerated through a potential difference V has de - Broglie wavelength lambda . The de - Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

An electron of mass m when accelerated through a potential difference V, has de Broglie wavelength lambda . The de Broglie wavelength associated with a proton of mass M accelerated through the same potential difference, will be :-

Find the de Broglie wavelength of an alpha particle accelerated through a potential difference of 100 V.

What is the de - Broglie wavelength of the alpha - particle accelerated through a potential difference V ?

An electron of mass m , when accelerated through a potential difference V , has de Broglie wavelength lambda . The de Broglie wavelength associated with a proton of mass M , accelerated through the same potential difference, will be