ABCDEF is a regular hexagon with point O as centre. The value of `vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF)` is

ABCDEF is a regular hexagon with point O as centre. Find the value of vec(AB) + vec(AC) + vec(AD) + vec(AE) + vec(AF)

ABCDEF is a regular hexagon, Fig. 2 (c ) .65. What is the value of (vec (AB) + vec (AC) + vec (AD) + vec (AE) + vec (AF) ? .

ABCDEF is a regular hexagon, Fig. 2 (c ) .65. What is the value of (vec (AB) + vec (AC) + vec (AD) + vec (AE) + vec (AF) ? .

In Fig. ABCDEF is a ragular hexagon. Prove that vec(AB) +vec(AC) +vec(AD) +vec(AE) +vec(AF) = 6 vec(AO) .

Consider the regular hexagon ABCDEF with centre at O (origin). Five forces vec(AB), vec(AC), vec(AD), vec(AE), vec(AF) act at the vertex A of a regular hexagon ABCDEF. Then their resultant is

Consider the regular hexagon ABCDEF with centre at O (origin). Five forces vec(AB), vec(AC), vec(AD), vec(AE), vec(AF) act at the vertex A of a regular hexagon ABCDEF. Then their resultant is -

ABCDEF is a regular hexagon. Show that : vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF)=6vec(AO) . Where O is the centre of the hexagon.