What is the escape velocity of the object, if.the magnitude of the potential energy per unit mass of the object at the surface of earth is `E`?

Define escape velocity of an object.

The magnitude of potential energy per unit mass of the object at the surface of earth is E . Then escape velocity of the object is

The magnitude of potential energy per unit mass of the object at the surface of earth is E . Then escape velocity of the object is

The magnitude of potential energy per unit mass of the object at the surface of earth is E . Then escape velocity of the object is

The magnitude of potential energy per unit mass of the object at the surface of earth is .E.. Then escape velocity of the object is

A particle of mass m is projected upwards with velocity v=(v_(e))/(2) , where v_(e) is the escape velocity then at the maximum height the potential energy of the particle is : (R is radius of earth and M is mass of earth)

A particle of mass m is projected upwards with velocity v=(v_(e))/(2) , where v_(e) is the escape velocity then at the maximum height the potential energy of the particle is : (R is radius of earth and M is mass of earth)