If `f={(-2,4),(0,6),(2,8)}` and `g= {(-2,-1),(0,3),(25)}`, then `((2f)/(3g)+(3g)/(2f))(0)=`

If f={(-2, 4), (0, 6), (2, 8)} and g={(-2, -1), (0, 3), (2, 5)} , then ((2f)/(3g)+(3g)/(2f))(0)=

If f={(a, 0), (b, 2), (c, -3)}, g={(a, -1), (b, 1), (c, 2)} then 2f-3g=

If f and g are two real functions defined by f={(a,1)(b,0),(c,8),(0,4)} and g={(a,5),(c,-3),(b,6)(0,2)} then dom ((sqrt(g))/(f)) is

If ={(a,1),(b,-2),(c,3)},g={(a,-2),(b,0),(c,1)} then f^(2)+g^(2)=

If f={(a, 1), (b, -2), (c, 3)}, g={(a, -2), (b, 0), (c, 1)} then f^(2)+g^(2)=

If f={(a, 0), (b, -2), (c, 3)}, g={a, -2), (b, 0), (c,1)} then f//g=

Let A ={1,2,3,4}. Let f : A to A " and " g : A to A defined by f : ={(1,4),(2,1),(3,3),(4,2)} and g = {(1,3),(2,1),(3,2),(4,4)} Find (i) g o f (ii) f o g (iii) f o f .

Let the functions f and g be defined by, f={(1,2),(2,3),(3,4),(4,1)} and g={(2,-1),(4,2),(1,-2),(3,4)} Show that, (g o f) is defined but (f o g) is not defined . Also find ( g o f) as set of ordered pairs.

Let f and g be two real functions given by f={(0,1),(2,0),(3,-4),(4,2),(5,-1)} and g={(1,0),(2,2),(3,-1),(4,4),(5,3)} then the domain of f*g is given by ..........