A charge Q is placed at the centre of a square If electric field intensity due to the charge at the corners of the square is `E_(1)` and the intensity at the mid point of the sidde of square is `E_(2)` then the ratio of `(E_(1))/(E_(2))` will be

Derive an expression for electric field intensity E due to an infinite place sheet of charge.

A circular copper ring of radius r, placed in vacuum, has charge q on it. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity on the axis of the ring at a distance x from its centre is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of E_(1) ?

A circular copper ring of radius r, placed in vacuum, has charge q on it. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity of the axis of the ring at a distance x from its centres is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of E_(2) ?

A circular copper ring of radius r, placed in vacuum, has charge q on ti. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity of the axis of the ring at a distance x from its centres is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of x' ?

Four charges each of charge (+q) are placed at the corners of square of side (0.1 meter). The net electric field intensity at the centre of the square is

Four charges +Q, -Q, +Q, -Q are placed at the corners of a square taken in order. At the centre of the square

Four identical charges i.e. q is placed at the corners of a square of side a . The charge Q that must be placed at the centre of the square such that the whole system of charges in equilibrium is

The electric field intensity at point near and outside the surface of a charged conductor of any shate is E_(1) the elecric field intensity due to uniformly charged conductor of any shape is E_(1) the electric field intensity due ot uniformly charged infinite thin plane sheet is E_(2) the relation between E_(1) and E_(2) is