A tyre pumped at a pressure of 3.375 atm and at `27^(@)C` suddenly bursts. What is the final temperature? `(gamma=1.5)`

A tyre pumped to a pressure 3.375 atm "at" 27^(@)C suddenly bursts. What is the final temperature (gamma = 1.5) ?

A tyre pumped to a pressure 3.375 atm "at" 27^(@)C suddenly bursts. What is the final temperature (gamma = 1.5) ?

A tyre is pumped to a pressure of 3.375 atmospheres and at 27^@C suddently bursts.What is the final temperature? (gamma=1.5) .

A tyre pumped to a pressure of 3.375 atmosphere and at 27^@C suddenly bursts . Calculate the temperature of escaping air . (y = 1.5)

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

The pressure of the air inside the motor tyre is 2 atmosphere and the temperature is 27^@C . If it suddenly bursts, the final temperature will be (gamma=1.4) :

A tyre pumped to a pressure of 6 atmosphere suddenly bursts. Room temperature is 25^(@)C . Calculate the temperature of escaping air. (gamma=1.4.)