Home
Class 11
CHEMISTRY
The degree of dissociation of N(2)O(4)(1...

The degree of dissociation of `N_(2)O_(4)(1)` obeying the equilibrium,
`N_(2)O_(4) (g) hArr 2NO_(2)(g)`, is approximately related to the pressure at equilibrium by `:`

Promotional Banner

Similar Questions

Explore conceptually related problems

The degree of dissociation of SO_(3) at equilibrium pressure is: K_(p) for 2SO_(3) (g)hArr2SO_(2)(g) + O_(2) (g)

For the equilibrium N_(2)O_(4(g))hArr 2NO_(2(g)) , the K_(p) and K_(c ) values are related as

For the equilibrium N_(2)O_(4(g))hArr 2NO_(2(g)) , the K_(p) and K_(c ) values are related as

For the equilibrium N_(2)O_(4(g))hArr 2NO_(2(g)) , the K_(p) and K_(c ) values are related as

For the equilibrium N_(2)O_(4(g))hArr 2NO_(2(g)) , the K_(p) and K_(c ) values are related as

The degree of dissociation 'alpha' of the reaction N_(2)O_(4)(g)hArr 2NO_(2)(g) Can be related of K_(p) as [Given : Total pressure at equilibrium = P]

If alpha is the degree of dissociation of N_(2)O_(4) in the reaction : N_(2)O_(4)hArr 2NO_(2) then at equilibrium, the total number of moles of N_(2)O_(4) and NO_(2) present is :

The degree of dissociation alpha of the reaction" N_(2)O_(4(g))hArr 2NO_(2(g)) can be related to K_(p) as: