If a,b,c are the ranks of `[(0,0,0),(0,0,0),(0,0,0)][(1,1,1),(1,1,1),(1,1,1)][(1,2,3),(2,4,7),(3,5,10)]` respectively then the ascending order of a,b,c is

If A,B,C are the values of the determinants |(0,1,1),(1,0,1),(1,1,0)|,|(1,4,2),(2,-1,4),(-3,7,6)|,|(2,-1,4),(4,-3,1),(1,2,1)| then the ascending order of A,B,C is

Find the rank of B= [[1,0,1,1],[0,0,1,2],[0,1,0,0],[0,0,0,1]]

If A=[(1,2,3),(2,0,-1),(0,2,-2)],B=[(1,0,0),(0,-1,0),(-1,0,2)] then 4A-3B=

If A={:[(3,2,7),(1,1,4),(-1,-1,0)]:},B={:[(1,0,3),(2,1,0),(0,-1,-3)]:}andC{:[(1,0,0),(0,1,0),(0,0,1)]:} , then find 2A+3B-7C.

If A={:[(2,-3),(0,1),(-1,4)],B={:[(-1,5),(2,-3),(0,1)],C={:[(4,-2),(0,-1),(3,5)], Find the matrices 2B - 3C

If A=[(1,0,-1),(2,1,0)], B=[(3,1),(-1,2),(0,1)] and C=[(4,2),(-3,0),(1,2)] show that AB=AC .

If A=[{:(0,6,7),(-6,0,8),(7,-8,0):}],B=[{:(0,1,1),(1,0,2),(1,2,0):}]andC=[{:(2),(-2),(3):}] then prove that (A+B)C=AC+BC.

If A=[(2),(0),(1)],B-[(4,-2,5)],C=[(0,1),(1,0),(-1,1)] then ABC=