1 mole of gas expands isothermally at `37^(@)C`. The amount of heat is absorbed by it until its volume doubled is `(R= 8.31 J mol^(-1) K^(-1))`

Calculate the molar specific heat at constant volume of neon gas. (R = 8.314 J mol^(-1) K^(-1) )

Calculate the molar specific heat of oxygen gas at constant volume. (R = 8.314 J mol^(-1) K^(-1) )

Calculate the molar specific heat at constant volume of neon gas. (R=8.314J mol^(-1)K^(-1) )

Calculate the molar specific heat at constant volume of neon gas. (R=8.314J mol^(-1)K^(-1) )

A gram mole of a gas at 27^@C expands isothermally until its volume is doubled. Calculate the amount of work done. (R=8 J mol^(-1) K^(-1))

Calculate the molar specific heat of oxygen gas at constant volume. (R=8.314" J "mol^(-1)K^(-1))

Calculate the molar specific heat of oxygen gas at constant volume. (R=8.314" J "mol^(-1)K^(-1))

A certain volume of a gas (diatomic) expands isothermally at 20^@C until its volume is doubled and then adiabatically until its volume is again doubled. Find the final temperature of the gas, given gamma = 1.4 and that there is 0.1 mole of the gas. Also calculate the work done in the two cases. R=8.3 J "mole"^(-1) K^(-1)