A 900 kg elevator hangs by a steel cable for which the allowable stress is `1.15xx10^8(N)/(m^2)`. What is the minimum diameter required if the elecator accelerates upward at `1.5(m)/(s^2)`? Take `g=10(m)/(s^2)`.

A 900 kg elevator hangs by a steel cable for which the allowable stress is 1.15xx10^(8)" N/m"^(2) . What is the minimum diameter required if the elevator accelerates upward at 1.5" m/s"^(2)?" Take "g=10" m/s"^(2) .

In the system shown in the adjoining figure, the acceleration of the 1 kg mass is m//s^(2) . (take g = 10 m//s^(2) )

Which would require a greater force - accelerating a 10 g mass at 5 m/ s^(2) or 20 g mass at 2 m/ s^(2) ?

The greatest length of a steel wire that can hang without breaking is 10 km. I the breaking stress for steel is 8.25xx10^(8)N//m^(2) . Then the density of the steel is (g=10m//s^(2))

A stress of 10^(6) N//m^(2) is required for breaking a material. If the density of the material is 3 xx 10^(3) Kg//m^(3) , then what should be the minimum length of the wire made of the same material so that it breaks by its own weight (g = 10m//s^(2))

A stress of 10^(6) N//m^(2) is required for breaking a material. If the density of the material is 3 xx 10^(3) Kg//m^(3) , then what should be the minimum length of the wire made of the same material so that it breaks by its own weight (g = 10m//s^(2))