`[((a^(0)+b^(0))(a^(0)-b^(0)))/(a^(2)-b^(2))]^(0^(+^(5)))" "("where "a ne 0 and b ne 0)` is

If a=b^2c , where a ne 0 and b ne 0 , then b/c =

Solve: (x)/(a) - (a+b)/(x)= (b(a-b))/(ax) , when x ne 0 and a ne 0 .

The non-zero solution of the equation (a-x^(2))/(bx) - (b-x)/(c) = (c-x)/(b) - (b - x^(2))/(c x) , where b ne 0, c ne 0 is

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}

Solve : (a)/(ax-1)+(b)/(bx-1)=a+b , where a+b ne 0, ab ne 0 .

Solve the following pair of equations for x and y : (a^(2))/(x)-(b^(2))/(y)=0, (a^(2)b)/(x)+(b^(2)a)/(y)=a+b , x ne 0 , y ne 0 .

Evaluate Lt_(xtooo)(a_(0)x^(m)+a_(1)x^(m-1)+...+a_(m))/(b_(0)x^(n)+b_(1)x^(n-1)+...+b_(n)) where m and n are positive integers and a_(0)ne0,b_(0)ne0 .

If a ne b ne 0 and a^(x)=b^(x) then x = ?