Voltage input in a circuit is V = 300 `sin (omega t)` with current = 100 `cos(omega t)` . Average power loss in the circuit is

For an ac circuit V=15 sin omega t and I=20 cos omega t the average power consumed in this circuit is

The voltage and current in an a.c. circuit are given by E = 300 sin (omega t + pi//2) and I = 5 sin omega t . What is power factor of the circuit and power dissipated in each cycle ?

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

Emf applied and current in an A.C. circuit are E=10sqrt(2) sin omega t volt and l=5sqrt(2)cos omega t ampere respectively. Average power loss in the circuit is

Emf applied and current in an A.C. circuit are E=10sqrt(2) sin omega t volt and l=5sqrt(2)cos omega t ampere respectively. Average power loss in the circuit is