Figure-5.150 shows LC circuit with initial charge on capacitor `200 mu C`. If at t=0 switch is closed, find the first instant when energy stored in inductor becomes one third that of capacitor.

The circuit shown in figure is in the steady state with switch S_(1) closed. At t=0, S_(1) is opened and switch S_(2) is closed. Find the first instant t, when energy in inductor becomes one third of that in capacitor

The circuit shown in figure is in the steady state with switch S_(1) closed. At t=0, S_(1) is opened and switch S_(2) is closed. Find the first instant t, when energy in inductor becomes one third of that in capacitor

The circuit shown in figure is in the steady state with switch S_(1) closed.At t=0 , S_(1) is opened and switch S_(2) is closed. The first instant t when energy in inductor becomes one third of that in capacitor is equal to (pi xx 10^(-5))/x sec . Then finout value of x .

The circuit shown in figure is in the steady state with switch S_(1) closed.At t=0 , S_(1) is opened and switch S_(2) is closed. The first instant t when energy in inductor becomes one third of that in capacitor is equal to (pi xx 10^(-5))/x sec . Then finout value of x .

Initial charge on capacitor of 3 mu C. Find initial current when switched is closed.

The circuit shows in Fig. is in the steady state with switch S_(1) closed. At t = 0,S_(1) is opened and switch S_(2) is closed. a. Derive expression for the charge on capacitor C_(2) as a function of time. b. Determine the first instant t , when the energy in the inductor becomes one-third of that in the capacitor.

The circuit shows in Fig. is in the steady state with switch S_(1) closed. At t = 0,S_(1) is opened and switch S_(2) is closed. a. Derive expression for the charge on capacitor C_(2) as a function of time. b. Determine the first instant t , when the energy in the inductor becomes one-third of that in the capacitor.

The capacitor shown in the figure is initially unchanged, the battery is ideal. The switch S is closed at time t= 0, then the time after which the energy stored in the capacitor becomes one - fourth of the energy stored in it in steady - state is :

The capacitor shown in the figure is initially unchanged, the battery is ideal. The switch S is closed at time t= 0, then the time after which the energy stored in the capacitor becomes one - fourth of the energy stored in it in steady - state is :