A line passing through (21,30) and normal to the curve `y=2sqrtx`. If m is slope of the normal then `m + 6 =`

Slope of normal to the curve y=x^2-x and x=2 is

The equation of the normal to the curve y^2=4ax having slope m

A curve y=f(x) passes through point P(1,1). The normal to the curve at P is a (y-1)+(x-1)=0. If the slope of the tangent at any point on the curve is proportional to the ordinate of the point,then the equation of the curve is

A curve y=f(x) passes through point P(1,1) . The normal to the curve at P is a (y-1)+(x-1)=0 . If the slope of the tangent at any point on the curve is proportional to the ordinate of the point, then the equation of the curve is

A curve y=f(x) passes through point P(1,1) . The normal to the curve at P is a (y-1)+(x-1)=0 . If the slope of the tangent at any point on the curve is proportional to the ordinate of the point, then the equation of the curve is

Find the slope of the normal to the curve y=xe^-x at x=2.

Find the slope of the normal to the curve y = x^3-xat x = 2

The slope of normal to the curve y = x^2 +3 at x=1 is

A curve passing through the point (1,2) and satisfying the condition that slope of the normal at any point is equal to the ratio of ordinate and abscissa of that point , then the curve also passes through the point

Slope of the normal to the curve y=cos2x "at" x=pi//6 is