The heat change for the reaction,
`N_(2)(g)+3H_(2)(g)to2NH_(3)(g)`
is -92.2kJ. Calculate the heat of formation of ammonia.

Heat change for a reaction N_(2)(g) + 3H_(2) (g) to 2NH_(3)(g) is - 92.2 kj/mol. Calculate the heat of formation of one mole of a ammonia.

The enthalpy change for the reaction N2(g) + 3 H2(g) → 2 NH3(g) is -91.8 kJ at 298 K. Calculate the enthalpy of formation of ammonia?

The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?

The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?

The enthalpy change for the reaction, N_2(g)+3H_2(g)rightarrow2NH_3(g) Is -92.38 kJ at 298 K. What is DeltaU at 298 K?

The enthaply change (Delta H) for reaction, N_(2) (g) + 3H_(2)(g) to 2NH_(3) (g) is 92.38 kj at 298 K. What is Delta U at 298 K ?