If the equation of the line is `x-ay+b=0` ; `z-cy+d=0` .Then its symmetric form is

The equation of the line x+y+z-1=04x+y-2z+2=0 written in the symmetrical form is

The equation of the line x+y+z-1=0 and 4x+y-2z+2=0 written in the symmetrical form is

The equation of straight line 3x+2y-2-4=0;4x+y-2z+3=0 in the symmetrical form is

Find the equation of line x+y-z-3=0=2x+3y+z+4 in symmetric form.Find the direction of the line.

Find the direction ratios of the line x+2y-z=3,2x-y+z=1 and its equation in a symmetrical form.

Show that the line represented by equation x=ay+b,z=cy+d in symmetric form is (x-b)/a=y/1=(z-d)/c

The Cartesian equations of a line are x=ay+b,z=cy+d. Find its direction ratios and reduce it to vector form.

The dr's of the line x=ay+b,z=cy+d are