If `int_cosx^1 t^2f(t)dt=1-cosx AA x in (0,pi/2)`, then the value of `[f(sqrt(3)/4)]` is

If int_(cos x)^(1)t^(2)f(t)dt=1-cos x AA x in(0,(pi)/(2)) then the value of [f((sqrt(3))/(4))] is

If int_(sinx)^(1)t^(2)f(t)dt=1-sinx, xepsilon(0,(pi)/2) then find the value of f(1/(sqrt(3)))

If int_(sinx)^1 t^2f(t)dt=1-sinx , then the value of f(1/sqrt(3)) is (A) 1/sqrt(3) (B) 1/3 (C) sqrt(3) (D) 3

Ifint_(sin x)^(1)t^(2)f(t)dt=1-sin x, wherex in(0,(pi)/(2)) then find the value of f((1)/(sqrt(3)))

If int_(sinx)^(1) t^(2)f(t)dt=1-sinx " for all " x in [0,pi//2] , then f((1)/(sqrt(3)))=

If int_(0)^(x) f(t)dt=x+int_(x)^(1) t f(t) dt , then the value of f(1), is

If int_(0)^(x^(2)(1+x))f(t)dt=x , then the value of f(2) is.