Home
Class 11
MATHS
The equation of the line through (3,1,2...

The equation of the line through (3,1,2) and equally inclined to the axes is
`(x-3)/(1)=(y-1)/(1)=(z-2)/(1)`
`(x-3)/(0)=(y-1)/(1)=(z-2)/(0)`
`(x-3)/(0)=(y-1)/(0)=(z-2)/(1)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the plane through the point (-1,2,0) and parallel to the lines (x)/(3)=(y+1)/(0)=(z-2)/(-1) and (x-1)/(1)=(y+1)/(2)=(2z+5)/(-1)

The equation of the line through the point (0,1,2) and perpendicular to the line (x-1)/(2)=(y+1)/(3)=(z-1)/(-2) is :

The equation of the plane through the point (-1,2,0) and parallel to the line (x)/(3)=(y+1)/(0)=(z-2)/(-1) and (x)/(3)=(2y+1)/(2)=(2z+1)/(-1) is

Find the equation of a line passing through (1,-1,0) and parallel to the line (x-2)/(3)=(2y+1)/(2)=(5-z)/(1)

Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0

The lines (x-1)/(3)=(y-1)/(-1),z=-1and(x-4)/(2)=(z+1)/(3),y=0

Find the equation of the line passing through A(0,1,2) and perpendicular to line (x-1)/2=(y+1)/2=(z-1)/3

Find the equation of the line passing through the point (-1,2,3) and perpendicular to the lines (x)/(2)=(y-1)/(-3)=(z+2)/(-2) and (x+3)/(-1)=(y+3)/(2)=(z-1)/(3)

Equation of the line passing through (1,1,1) and perpendicular to the plane 2x+3y-z-5=0 is

The equation of the plane which is equally inclined to the lines (x-1)/(2)=(y)/(-2)=(z+2)/(-1) and =(x+3)/(8)=(y-4)/(1)=(z)/(-4) and passing through the origin is/are a.14x-5y-7z=0 b.2x+7y-z=0 c.3x-4y-z=0 d.x+2y-5z=0