Home
Class 11
MATHS
The equation of the line through (3,1,2...

The equation of the line through (3,1,2) and equally inclined to the axes is
`(x-3)/(1)=(y-1)/(1)=(z-2)/(1)`
`(x-3)/(0)=(y-1)/(1)=(z-2)/(0)`
`(x-3)/(0)=(y-1)/(0)=(z-2)/(1)`

Answer

Step by step text solution for The equation of the line through (3,1,2) and equally inclined to the axes is (x-3)/(1)=(y-1)/(1)=(z-2)/(1)(x-3)/(0)=(y-1)/(1)=(z-2)/(0)(x-3)/(0)=(y-1)/(0)=(z-2)/(1) by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The equation of the plane through the point (-1,2,0) and parallel to the lines (x)/(3)=(y+1)/(0)=(z-2)/(-1) and (x-1)/(1)=(y+1)/(2)=(2z+5)/(-1)

The equation of the plane through the point (-1,2,0) and parallel to the line (x)/(3)=(y+1)/(0)=(z-2)/(-1) and (x)/(3)=(2y+1)/(2)=(2z+1)/(-1) is

Knowledge Check

  • The equation of the line through the point (0,1,2) and perpendicular to the line (x-1)/(2)=(y+1)/(3)=(z-1)/(-2) is :

    A
    `(x)/(3)=(y-1)/(4)=(z-2)/(3)`
    B
    `(x)/(3)=(y-1)/(-4)=(z-2)/(3)`
    C
    `(x)/(3)=(y-1)/(4)=(z-2)/(-3)`
    D
    `(x)/(-3)=(y-1)/(4)=(z-2)/(3)`

  • The lines (x-1)/(3)=(y-1)/(-1),z=-1and(x-4)/(2)=(z+1)/(3),y=0

    A
    do not intersect
    B
    intersect at `(4,1,-2)`
    C
    intersect at `(4,0,-1)`
    D
    intersect at `(1,1,-1)`

  • Equation of the line passing through (1,1,1) and perpendicular to the plane 2x+3y-z-5=0 is

    A
    `(x-1)/2=(y-1)/3 =(z-1)/1`
    B
    `(x-1)/2=(y-1)/3=(z-1)/-1`
    C
    `(x-1)/2=(y-1)/-1=(z-1)/1`
    D
    None of the above

    • Similar Questions

    Explore conceptually related problems

    Find the equation of a line passing through (1,-1,0) and parallel to the line (x-2)/(3)=(2y+1)/(2)=(5-z)/(1)

    Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0

    Find the equation of the line passing through A(0,1,2) and perpendicular to line (x-1)/2=(y+1)/2=(z-1)/3

    Find the equation of the line passing through the point (-1,2,3) and perpendicular to the lines (x)/(2)=(y-1)/(-3)=(z+2)/(-2) and (x+3)/(-1)=(y+3)/(2)=(z-1)/(3)

    The equation of the plane which is equally inclined to the lines (x-1)/(2)=(y)/(-2)=(z+2)/(-1) and =(x+3)/(8)=(y-4)/(1)=(z)/(-4) and passing through the origin is/are a.14x-5y-7z=0 b.2x+7y-z=0 c.3x-4y-z=0 d.x+2y-5z=0

    Home
    Profile