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Solution of the differential equation 2y...

Solution of the differential equation `2y sin x(dy)/(dx)=2sinx cosx-y^(2)cos x` satisfying `y((pi)/(2))=1` is given by
(A) `y=sin^(2)x`
(B) `y^(2)=sin x`
(c) `y^(2)=cos x+1`
(D) `y^(2)sin x=4cos^(2)x`

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