A 2.0m long string with a linear mass density of `5.2xx10^(-3) kg m^(-1)` and tension 52N has both of its ends fixed. It vibrates in a standing wave patten with four antinodes. Frequency of the vibraion is :-

Power supplied to a vibrating string: A string with linear mass density mu=5.00xx10^(-2) kg//m is under a tension of 80.0 N. how much power must be supplied to the string to generate sinusoidal waves at a frequancy of 60.0 HZ and an amplitude of 6.00 cm?

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of 2 xx 10^(-3) kg//m that passes over a light pulley . The string is connected to a vibrator of frequency 700 Hz and the length of the string between the vibrator and the pulley is 1 m . If the standing waves are observed , the largest mass to be hung is

The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string 4 xx 10^(-3) kg m^(-1) . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment . (A) The fundamental frequency of the vibratinng string is , n = (1)/(2l) sqrt((T)/(m)) . (B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem . (C) Calculate the tension in the string using , T = mg . (D) Substitute the appropriate values in n = (1)/(2l) sqrt((T)/(m)) and find the value of 'n' .

Figure shows different standing wave patterns on a string of linear mass density 4.0 xx 10^-2 kg//m under a tension of 100 N. The amplitude of antinodes is indicated in each figure. The length of the string is 2.0m. (i) Obtain the frequencies of the modes shown in figures (a) and (b). (ii)Write down the transverse displacement y as a function of x and t for each mode. (Take the initial configuration of the wire in each mode to be as shown by the dark lines in the figure).

A sting of length 1m and linear mass density 0.01 kg//m is stretched to a tension of 100 N. When both ends of the string are fixed, the three lowest frequencies for standing wave are f_1, f_2 and f_3 . When only one end of the string is fixed, the three lowest frequencies for standing wave are n_1, n_2 and n_3 . Then,

A string of length 0.5m and linear density 10^(-4) kg/m is stretched under a tension of 100 N. If the frequency of the vibration of the string is 4000 Hz, how many loops are formed on the string?

A 20 cm long string, having a mass of 1.0 g, is fixed at both the ends. The tension in the string is 0.5 N. The string is set into vibrations using an external vibrator of frequency 100 Hz. Find the separation (in cm) between the successive nodes on the string.

A 20 cm long string, having a mass of 1.0g , is fixed at both the ends. The tension in the string is 0.5 N . The string is into vibrations using an external vibrator of frequency 100 Hz . Find the separation (in cm) between the successive nodes on the string.

A stretched rope having linear mass density 5xx10^(-2)kg//m is under a tension of 80 N . the power that has to be supoplied to the rope to generate harmonic waves at a frequency of 60 Hz and an amplitude of (2sqrt2)/(15pi)m is