A particle of mass 2.4kg is having a velocity of `(3hati+4hatj)m/s` at (5,6)m.The angular momentum of the particle about (1,2)m ,in `kgm^(2)/s` ,is?

A particle having mass 2 kg is moving with velcoity (2 hat(i) + 3 hat(j))m//s . Find angular momentum of the particle about origin when it is at (1, 1, 0).

A particle of mass 1kg is moving about a circle of radius 1m with a speed of 1m//s . Calculate the angular momentum of the particle.

A particle of mass 1 kg is moving alogn the line y=x+2 with speed 2m//sec . The magnitude of angular momentum of the particle about the origin is

A particle of mass 2 kg located at the position (hati + hatj)m has velocity 2(hati - hatj + hatk) m//s . Its angualr momentum about Z-axis in kg m^(2)//s is

A particle having mass 2 kg is moving along straight line 3 x + 4 y = 5 with speed 8m//s . Find angular momentum of the particle about origin, x and y are in meters.

The moment of Inertia of a particle about an axis of rotation is 0.2kgm^(2) .If the angular momentum of the particle about the axis is 0.4kgm^(2)/s ,then what is the rotational kinetic energy of the particle?

A particle of mass 2 kg is projected with a velocity (6 hat(i) + 8 hat(j)) m/s. Find the magnitude of change in momentum (in kg m/s) when it just touches ground again.

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

A particle of mass 2 kg is moving such that at time t, its position, in meter, is given by vecr(t)=5hati-2t^(2)hatj . The angular momentum of the particle at t = 2s about the origin in kg m^(-2)s^(-1) is :

A particle of mass 1kg moves along the curve y=x^(2) Magnitude of angular momentum of the particle about origin,when particle has x co-ordinate is (1)/(2)m and x-component of velocity is 4m/s is