इन को ` a + ib ` के रूप में व्यक्त कीजिये |
` ( 1 + 2i + 3i ^ 2 ) /( 1 - 2i + 3i^ 2 ) `

If a + ib = (1 + i) / (1 - i) , prove that a^2 + b^2 = 1

Write (1 +2i ) (1 + 3i ) ( 2 + i ) ^(-1) in the form a + ib

(1+2i+3i^2)/(1-2i+3i^2) equals a. i b. -1 c. -i d. 4

(1+2i+3i^(2))/(1-2i+3i^(2)) equals i b.-i c.-1 d.4

Express the following in the form a+ib: (1+2i+3i^2)/(1-2i+3i^2)

Express the follwing in the form of a + ib, a , b in R i=sqrt ( -1). State the value of a and b. ( ( 2 + i ))/( ( 3 - i ) (1 + 2i ))

Express (1+3i)/(1-2i) in the form a+ib .