If a circle of radius R passes through the origin O and intersects the coordinates axes at A and B, then the locus of the foot of perpendicular from O on AB is:

A circle of constant radius r passes through the origin O and cuts the axes at A and B. Show that the locus of the foot of the perpendicular from O to AB is (x^2+y^2)^2(x^(-2)+y^(-2))=4r^2 .

A circle of constant radius r passes through the origin O and cuts the axes at A and B. Show that the locus of the foot of the perpendicular from O to AB is (x^2+y^2)^2(x^(-2)+y^(-2))=4r^2 .

A circle of constant radius 5 units passes through the origin O and cuts the axes at A and B. Then the locus of the foot of the perpendicular from O to AB is (x^(2)+y^(2))^(2)(x^(-1)+y^(-2))=k then k=

A circle of constant radius r passes through the origin O, and cuts the axes at A and B. The locus of the foots the perpendicular from O to AB is (x^(2) + y^(2)) =4r^(2)x^(2)y^(2) , Then the value of k is

A circle of constant radius r passes through the origin O, and cuts the axes at A and B. The locus of the foots the perpendicular from O to AB is (x^(2) + y^(2))^k =4r^(2)x^(2)y^(2) , Then the value of k is

A circle of constant radius a passes through the origin O and cuts the axes of coordinates at points P and Q . Then the equation of the locus of the foot of perpendicular from O to P Q is

A circle of radius r passes through the origin and meets the axes at A and B. The locus of the centroid of triangleOAB" is"

A circle of radius r passes through the origin and meets the axes at A and B. The locus of the centroid of triangleOAB" is"