The time period `T` of a simple pendulum depends on length `L` and acceleration due to gravity `g` Establish a relation using dimensions.

How time period of a simple pendulum depends on the acceleration due to gravity ?

State how does the time period of a simple pendulum depend on acceleration due to gravity.

Consider a simple pendulum. The period of oscillation of the simple pendulum depends on its length and acceleration due to gravity. Then the expression for its time period is

Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is pi^2ms^-2 .

Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is pi^2ms^-2 .

The period of oscillation of a simple pendulum at a given place with acceleration due to gravity 'g' depends on

Time period of simple pendulum of length l at a place, where acceleration due to gravity is g and period T. Then period of simple pendulum of the same length at a place where the acceleration due to gravity 1.02 g will be

An expression for the time period of oscillation of a simple pendulum of length 'L' at a place where acceleration due to gravity is g is T prop ((L)/(g))^((1)/(x)) , then the vaslue of x is