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What is the derivative of (log(tanx)cotx...

What is the derivative of `(log_(tanx)cotx)(log_(cotx)tanx)^(-1)` at `x=(pi)/(4)`?

A

`-1`

B

0

C

1

D

`(1)/(2)`

Text Solution

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The correct Answer is:
To find the derivative of the function \( f(x) = \left( \log_{\tan x} \cot x \right) \left( \log_{\cot x} \tan x \right)^{-1} \) at \( x = \frac{\pi}{4} \), we can follow these steps: ### Step 1: Simplify the Function First, we can rewrite the logarithmic expressions using the change of base formula: \[ \log_{\tan x} \cot x = \frac{\log \cot x}{\log \tan x} \] \[ \log_{\cot x} \tan x = \frac{\log \tan x}{\log \cot x} \] Thus, we can express \( f(x) \) as: \[ f(x) = \frac{\log \cot x}{\log \tan x} \cdot \left( \frac{\log \tan x}{\log \cot x} \right)^{-1} \] ### Step 2: Simplify Further The term \( \left( \frac{\log \tan x}{\log \cot x} \right)^{-1} \) can be rewritten as: \[ \left( \frac{\log \tan x}{\log \cot x} \right)^{-1} = \frac{\log \cot x}{\log \tan x} \] Now substituting this back into \( f(x) \): \[ f(x) = \frac{\log \cot x}{\log \tan x} \cdot \frac{\log \cot x}{\log \tan x} = \left( \frac{\log \cot x}{\log \tan x} \right)^2 \] ### Step 3: Evaluate at \( x = \frac{\pi}{4} \) At \( x = \frac{\pi}{4} \): \[ \tan\left(\frac{\pi}{4}\right) = 1 \quad \text{and} \quad \cot\left(\frac{\pi}{4}\right) = 1 \] Thus: \[ \log \tan\left(\frac{\pi}{4}\right) = \log 1 = 0 \quad \text{and} \quad \log \cot\left(\frac{\pi}{4}\right) = \log 1 = 0 \] This means: \[ f\left(\frac{\pi}{4}\right) = \left( \frac{\log 1}{\log 1} \right)^2 = \left( \frac{0}{0} \right)^2 \] This is an indeterminate form, so we need to apply L'Hôpital's Rule or analyze the limit. ### Step 4: Find the Derivative To find the derivative \( f'(x) \), we can use the quotient rule and chain rule. However, since we found that \( f\left(\frac{\pi}{4}\right) \) leads to an indeterminate form, we can analyze the behavior around \( x = \frac{\pi}{4} \). Given that both \( \log \tan x \) and \( \log \cot x \) approach \( 0 \) as \( x \) approaches \( \frac{\pi}{4} \), we can conclude that \( f(x) \) is constant around this point. ### Conclusion Thus, the derivative \( f'(x) \) at \( x = \frac{\pi}{4} \) is: \[ f'\left(\frac{\pi}{4}\right) = 0 \]

To find the derivative of the function \( f(x) = \left( \log_{\tan x} \cot x \right) \left( \log_{\cot x} \tan x \right)^{-1} \) at \( x = \frac{\pi}{4} \), we can follow these steps: ### Step 1: Simplify the Function First, we can rewrite the logarithmic expressions using the change of base formula: \[ \log_{\tan x} \cot x = \frac{\log \cot x}{\log \tan x} \] \[ ...
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