What is the equation of the straight line which passes through the point of intersection of the straight lines `x+2y=5` and `3x+7y=17` and is perpendicular to the straight line `3x+4y=10` ?

Options

A. `4x+3y+2=0`
B. `4x-y+2=0`
C. `4x-3y-2=0`
D. `4x-3y+2=0`

Answer

D

Explanation

Intersecting lines are : `x+2y=5` & `3x+7y=17`
On solving these we get : `x=1` & `y=2`
Equation of perpendicular line is
`3x+4y=10 or y=(-3)/4x+10`
So, slope `=(-3)/4`
`implies` Slope of required line `=4/3`
`:.` Equation of given line is
`(y-2)=4/3 (x-1) or 4x-3y+2 =0`