Home
Class 12
MATHS
What is the last digit of 3^(3^(4n)) +1,...

What is the last digit of `3^(3^(4n)) +1`, where n is a natural number?

A

2

B

7

C

8

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

In `3^(n)`, last digit is 3, if n=1,9 if n=2,7 if n=3 and 1 if
n=4 and it is repeated after than
Given expression is `3^(3^(4n))+1`
Let `x=3^(3^(4n))+1=3^(8"In")+1`
`rArr" "x=3^(80n).3^(n)+1`
Last digit of x will be decided by `3^(n)" since "3^(80n)` has power multiple of 4.
If n=1 last digit is 3+1=4
n=2 last digit is `3^(2)+1=9+1=10`
So, last digit is zero.
n=3 last digit is `3^(3)+1=27+1=28`
last digit is 8.
If n=4 last digit is `3^(4)+1=81+1=82`
last digit is 2.
So, there is no definite value of last digit.
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the last digit of 3^(3n)+1, where n is a natural number?

The last digit of 3^(3^(4n))+1 , is

The last digit of (3^(P)+2), where P=3^(4n+2) is

If the sum of the digits of a number 10^(n) - 1 , where n is a natural number, is equal to 3798, then what is the value of n ?

What is the sum of the coefficients of first and last terms in the expansion of (1 + x)^(2n) , where n is a natural number?

If the sum of the digits of a number (10^(n)-1) is 4707, where n is a natural number,then the value of n is :

The unit digit of (316)^(3^(4n)) + 1 is :

The unit digit of (316^3)^(4n) + 1 is