Home
Class 11
PHYSICS
A particle is executing simple harmonic ...

A particle is executing simple harmonic motion of amplitude 5 cm and period 6 s. How long will it take to move from one end of its path on one side of mean position to a position 2.5 cm on the same side of the mean position ?

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is executing simple harmonic motion of amplitude 12 cm and time period 3 s. Calculate the time required by the particle to move between two points 6 cm on either side of mean position.

A particle is executing simple harmonic motion of amplitude 'a'.At what distance from mean position is its kinetic energy equal to its potential energy ?

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

A particle executing a simple harmonic motion has a period of 6 sec.The time taken by the particle to move from the mean position to half the amplitude is

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is