The freezing point of a solution containing 4.8 g of a compound in 60 g of benezene is `4.48 ^(@) C ` what is the molar mass of the compound ? `(k_(f)=5.1 Km^(-1)`, freezing point of benezene `=5.5^(@)C `)

The freezing point of a solution containing 4.8 g of a compound in 60 g of benzene is 4.48 ^(@) C . What is the molar mass of the compound ? (K_(f)=5.1 Km^(-1) , freezing point of benzene =5.5^(@)C )

The freezing point of a solution containing 4.8 g of a compound in 60 g of benzene is 4.48. What is the molar mass of the compound ? ( K_(f)=5.1 Km^(-1) , freezing point of benzene =5.5^(@)C )

The freezing point of a solution containing 2.40 g of a compound in 60.0g of benzene is 0.10^(@)"C" lower than that of pure benzene. What is the molecular weight of the compound? ("K"_("f")" is " 5.12^(@)"C"//"m for benzene"

Phenol associates in benzene to from dimer (C_(6)H_(5)OH)_(2) . The freezing point of a solution containing 5g of phenol in 250 g of benzene is lowered by 0.70^(@)C . Calculate the degree of association of phenol in benzene .( k_(f) for benzene = 5.12 Km^(-1) )

What would be the freezing point of aqueous solution containing 17 g of C_2H_5OH in 1000 g of water K_f = 1.86 K molality^-1 :