A vessel at `100K` contains `CO_(2)` with a pressure of 0.5 atm. Some of the `CO_(2)` is converted into CO on addition of graphite. Calculate the value of K if total pressure at equilibrium is 0.8 atm.

A vessel of '1000 K' contains 'CO_2', with a pressure of '0.5 atm .' Some of the 'CO_2' converted into 'CO' on the addition of graphite. The value of 'K' if the total pressure at equilibrium is '0.8 atm'. is:

A vessel at 1000 K contains CO_(2) with a pressure of 0.5 atm. Some of the CO_(2) is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is :

A vessel at 1000K contains CO_2 with a pressure of 0.5 atm. Some of the CO_2 is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8atm. The value of K is

A vessel at 1000 K contains CO_(2) with a pressure of 0.5 atm. Some of CO_(2) is converted into CO on addtion of graphite. The value of K' at equilibrium when total pressure is 0.8 atm will be