Two small balls of mass m each are suspended side by side by two equal threds to length L. If the distance between the upper ends of the threads be a, the angle `theta` that the threads will make with the vertical due to attraction between the balls is :

Two metallic balls of mass m are suspended by two strings of length L . The distance between upper ends is l . The angle at which the string will be inclined with vertical due to attraction is (m lt lt M where M is the mass of Earth)

Two metallic balls of mass m are suspended by two strings of length L . The distance between upper ends is L . The angle at which the string will be inclined with vertical due to attraction is (m lt lt M where M is the mass of Earth)

Two metallic balls of mass m are suspended by two strings of length L . The distance between upper ends is l . The angle at which the string will be inclined with vertical due to attraction is (m lt lt M where M is the mass of Earth)

Two balls of mass m each are hung side by side by side by two long threads of equal length l. If the distance between upper ends is r, show that the distance r' between the centres of the ball is given by g r'^(2)(r-r')=2l G m

Two small identical balls, each of mass 0.20 g, carry identical charges and are suspended by two threads of equal lengths. The balls position themselves at equilibirum such that the angle between the threads is 60^(@) . If the distance between the balls is 0.5 m, find the charge on each ball.

A small sphere of mass m suspended by a thread is first taken a side so that the thread forms the right angle with the vertical and then released, then

Two identical tennis balls each having mass 'm' and charge 'q' are suspended from a fixed point by threads of length 'l'. What is the equilibrium separation when each thread makes a small angle 'theta' with the vertical ?