A stone falls freely from rest from aheight `h` and it travels a distance `h//2` in the last second. The time of journey is

A stone falls freely from rest from aheight h and it travels a distance 9h//25 in the last second. The value of h is

A particle is dropped under gravity from rest from a height h(g = 9.8 m//sec^2) and it travels a distance 9h//25 in the last second, the height h is.

A particle is droped under gravety from rest a height h and it travels a distance (9h)/(25) in the last second, the height h is (take g=9.8ms^(-2) )

A body is dropped from rest from a height h. It covers a distance (9h)/(25) in the last seconds of fall. The height h is : (use g = 9.8 m//sec^(2) )

A stone falls freely from rest and the total distance covered by it in the last second of its motion equals to the distance covered by it in the first three seconds of its motion. What much time for the stone remains in air?

A particle is dropped under gravity from rest from a height h (g = 9.8m/s^2 ) and it travels and it travels a distance of 9h/25 in the last second the height is