A force `vec F = (5 vec i+ 3 vec j+ 2 vec k) N` is applied over a particle which displaces it from its origin to the point `vec r=(2 vec i- vec j) m`. The work done on the particle in joules is.

A force vec(F) = (5hat(i) + 3hat(j)) N is applied over a particle which displaces it from its origin to the point vec(r ) = (2hat(i) - 1hat(j)) meter. The work done on the particle is :

A force vec(F) = (5hat(i) + 3hat(j)) N is applied over a particle which displaces it from its origin to the point vec(r ) = (2hat(i) - 1hat(j)) meter. The work done on the particle is :

A force vec(F)=(5hat(i)+3hat(j)+2hat(k))N is applied over a particle which displaces it from its origin to the point vec(r)=(2hat(i)-hat(j))m . The work done on the particle in joules is-

A vec(F) = (5hat(i) +3hat(j) +2hat(k))N is applied over a particle which displaces it from its origin to the point vec(r ) = (2 hat(i) - hat(j))m . The work done on the particle in joule is ……….

A force F = (2 vec i + vec j + vec k)N is acting on a particle moving with constant velocity vec v = (vec i + 2 vec j + vec k)m/s . Power delivered by force is

A Force vec(F)= 2vec(i) - lamda vec(j) + 5vec(k) is applied at the point A(1,2,5). If its moment about the point (-1, -2, 3) is 16 vec(i)-6 vec(j) + 2lamda vec(k) , then lamda=

The position vectors of the points A and B are vec i + 2 vec j + 3 vec k and 2 vec i - vec j - vec k respectively. Find the projection of vec (AB) on the vector vec i + vec j + vec k . Also find the resolved part of vec (AB) in that direction.

A particle is displaced from a position (2 vec i - vec j + vec k) metre to another position (3 vec i + 2 vec j -2 vec k) metre under the action of force (2 vec i + vec j -vec k) N. Work done by the force is

If a force vec(F) = (vec(i) + 2 vec(j)+vec(k)) N acts on a body produces a displacement of vec(S) = (4vec(i)+vec(j)+7 vec(k))m , then the work done is

A point on the line r=2vec i+3vec j+4vec k+t(vec i+vec j+vec k) is