Force constant of a weightless spring is 16 N/m. A body of mass 1.0 kg suspended from it is pulled down through 5 cm from its mean position and the released. The maximum kinetic energy of the system (spring+body) will be (0.0x) J. Find value of x.

Force constant of a weightless spring is 16 Nm^(-1) . A body if mass 1 kg suspended from it is pulled down through 5 cm from its mean position and then released. The maximum kinetic energy of the body will be

Force constant of a weightless spring is 16 Nm^(-1) . A body if mass 1 kg suspended from it is pulled down through 5 cm from its mean position and then released. The maximum kinetic energy of the body will be

The force constant of a weightless spring is 16 N m^(-1) . A body of mass 1.0 kg suspended from it is pulled down through 5 cm and then released. The maximum energy of the system (spring + body) will be

The force constant of a weightless spring is 16 N m^(-1) . A body of mass 1.0 kg suspended from it is pulled down through 5 cm and then released. The maximum energy of the sysytem (spring + body) will be

A body of mass 100 gm is suspended from a light spring which stretches it by 10 cm. Find the force constant of the spring.

A body of mass 100 gram is suspended from a light spring which stretches it by 10 cm. Find the force constant of the spring.

A spring has a natural length of 50 cm and a force constant of 2.0 xx 10^(3) N m^(-1) . A body of mass 10 kg is suspended from it and the spring is stretched. If the body is pulled down to a length of 58 cm and released, it executes simple harmonic motion. The net force on the body when it is at its lowermost position of its oscillation is (10x) newton. Find value of x. (Take g=10m/ s^(2) )

A spring has a natural length of 50 cm and a force constant of 2.0 xx 10^(3) N m^(-1) . A body of mass 10 kg is suspended from it and the spring is stretched. If the body is pulled down to a length of 58 cm and released, it executes simple harmonic motion. The net force on the body when it is at its lowermost position of its oscillation is (10x) newton. Find value of x. (Take g=10m/ s^(2) )

A spring has a natural length of 50 cm and a force constant of 2.0 xx 10^(3) N m^(-1) . A body of mass 10 kg is suspended from it and the spring is stretched. If the body is pulled down to a length of 58 cm and released, it executes simple harmonic motion. The net force on the body when it is at its lowermost position of its oscillation is (10x) newton. Find value of x. (Take g=10m/ s^(2) )